What is the theoretical yield of oxygen, in units of grams, when 108 g of KO. Chemistry Chemistry questions and answers Consider the reactionMg2Si (s)+4H2O (L)=2Mg (OH)2 (aq)+SiH4 (g)How many moles of excess reactant are left over if we start with 39.1 g of each reactant? Solved If 24.7 g of NO and 13.8 g of O2 are used to form - Chegg Let's say you are asked to find how many grams of oxygen are produced when you react 0.2 grams of ozone. In this example, imagine that the tires and headlights are reactants while the car is the product formed from the reaction of 4 tires and 2 headlights. 6. Ammonia has a molar mass of 17 \ "g/mol". The chlorine will be completely consumed once 4 molesHCl have been produced. If not, identify the limiting reagent. 3.643 mols Si x 28.09 g / mol = 102.3 g Si left over after the reaction Worked example: Calculating amounts of reactants and products Is easily irritated. The ratio is 6 mole oxygen per 1 mole glucose, OR 1 mole oxygen per 1/6 mole glucose. People, especially those with numerous moles, should check them regularly for changes in size, color or shape. To understand this, you need to be familiar with the molar ratio or mole ratio. Thus, we can read this reaction as two moles of hydrogen react with one mole of oxygen to produce two moles of water.. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. How do you determine how much of the excess reactant is left over? Also With 14 headlights, 7 cars can be built (each car needs 2 headlights). 1 / 22 Flashcards Learn Test Match Created by Noelle_Jewell9 yuck. Accessibility StatementFor more information contact us atinfo@libretexts.org. Chemistry Chemistry questions and answers If 20.4 g of NO and 13.8 g of O are used to form NO, how many moles of excess reactant will be left over? With 20 tires, 5 cars can be produced because there are 4 tires to a car. How Much of the Excess Reactant Remains after a Reaction: https://youtu.be/K2II-QuBsKs. Mass of excess reagent calculated using the limiting reagent: \[\mathrm{2.40\:g\: Mg \times \dfrac{1.00\: mol\: Mg}{24.31\:g\: Mg} \times \dfrac{1.00\: mol\: O_2}{2.00\: mol\: Mg} \times \dfrac{32.0\:g\: O_2}{1.00\: mol\: O_2} = 1.58\:g\: O_2} \nonumber \]. A dermatologist is a medical doctor who specializes in treating the skin, hair, and nails. Here, learn how to tell if an itchy mole warrants a professional examination, and find other skin changes to check for. both reactant are consumed completelyb. Check out the simulation below for examples that review the concept of limiting reactants and excess reactants and applies the concept to making sandwiches and molecules. They can be gray, brown, yellowish, or black. We alsolearned that thetheoretical yieldis the maximum amount of product that may be made when all of the limiting reactant is converted to product. We avoid using tertiary references. Use stoichiometry for each individual reactant to find the mass of product produced. View this interactive simulation illustrating the concepts of limiting and excess reactants. #"NH"_3# is the only other reactant, so it is the excess reactant. If 3.0 moles of x and 4.0 moles of y react according to the For example, this equation is also balanced if we write it as, The ratio of the coefficients is 4:2:4, which reduces to 2:1:2. Melanocytes are melanin-producing cells. Identify the limiting reactant and the excess reactant. = 3.0 moles of 4.0 moles of B . Whichever value comes out less represents the limiting reactant. In this scenario, the number of sandwiches prepared has been limited by the number of cheese slices, and sixbread slices have been provided in excess. 8.6: How Much of the Excess Reactant Remains after a Reaction is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts. The most common examples being H2, N2, O2, F2, and Cl2. A similar situation exists for many chemical reactions: you usually run out of one reactant before all of the other reactant has reacted. Limiting & Excess Reactants Flashcards | Quizlet Problem 4.10PAE: 4.10 How many moles of oxygen can be obtained by the decomposition of 7.5 mol of reactant in each of. The reaction of \(4.20 \: \text{mol}\) of hydrogen with excess nitrogen produces \(2.80 \: \text{mol}\) of ammonia. Answered: If 23.3 g of NO and 13.8 g of O are | bartleby While melanoma is the most serious problem a mole can cause, it's not the only one. Problem 4.11PAE: 4.11 MTBE, C5H12O, is one of the additives that replaced tetraethyl-lead in gasoline. \[\ce{ C6H_{12}O6 + 6 O_2 \rightarrow 6 CO2 + 6 H2O} + \rm{energy} \nonumber \]. By the same token, the ratios we constructed to describe a molecular reaction can also be constructed in terms of moles rather than molecules. Barnhill RL and Rabinovitz H. Benign melanocytic neoplasms. In: Bolognia JL, et al. Limiting Reagents is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Sarick Shah. You need to start with the limiting reactant and convert that quantity into the grams of excess reactant. Find out how you can enjoy summer while reducing flare-ups. When there is not enough of one reactant in a chemical reaction, the reaction stops abruptly. 4 KO2 (s) + 2 H2O (l) 4 KOH (s) + 3 O2 (g). Staley, Dennis. Answer: 1.0 mol of A should be left over. One way of finding the limiting reagent is by calculating the amount of product that can be formed by each reactant; the one that produces less product is the limiting reagent. When a mole is a problem, its best to have a dermatologist examine it and decide whether it needs to be removed. However, it's good to know the procedure for when you come across more complicated problems to solve. Step 4: Use the amount of limiting reactant to calculate the amount of CO2 or H2O produced. 4 KO2 (s) + 2 H2O (l) 4 KOH (s) + 3 O2 (g). Number of moles on right arm could predict risk of deadly skin cancer. 5.00 gRbarecombined with 3.44 g MgCl2according to thechemical reaction: 2 Rb (s) + MgCl2 (s) Mg (s) + 2 RbCl (s). A bleeding or itchy mole can be a sign of melanoma. Find out what can help. The first step is to find how many moles of ozone are in 0.2 grams. B. Legal. Congenital melanocytic nevi are present at birth, any moles appearing after birth are melanocytic nevi. Because there are only 0.568 moles of H2F2, it is the limiting reagent. Balance the following unbalanced equation and determine how many moles of \(\ce{H2O}\) are produced when 1.65 mol of NH. If the ratio is unbalanced, there will be leftover reactant. What is an example of a limiting reagent practice problem? around the world. Solved If 20.4 g of NO and 13.8 g of O are used to form - Chegg Youre more likely to spot melanoma early if you know: To make it easy for you to know your moles, the AAD worked with dermatologists to create the Body Mole Map. N2 (g) + 3H2 (g) -->2 NH3 (g) The equation above is the equation for the Haber process. Since we have 0.11 moles of nitrogen, then we make 0.11*2=0.22 moles of ammonia gas. This means: 6 mol O2 / 1 mol C6H12O6 . Solved Iron(III) oxide (F0,0z) can be converted into iron | Chegg.com This pageis shared under aCC BY-NC-SA 4.0license and was authored, remixed, and/or curated by Sarick Shah, Lance S. Lund (Anoka-Ramsey Community College),Marisa Alviar-Agnew, and Henry Agnew. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. This substance is the limiting reactant, and the other substance is the excess reactant. For the example in the previous paragraph, the complete reaction of the hydrogen would yield, \[\mathrm{mol\: HCl\: produced=6\: mol\:H_2\times \dfrac{2\: mol\: HCl}{1\: mol\:H_2}=12\: mol\: HCl}\], The complete reaction of the provided chlorine would produce, \[\mathrm{mol\: HCl\: produced=4\: mol\:Cl_2\times \dfrac{2\: mol\: HCl}{1\: mol\:Cl_2}=8\: mol\: HCl}\]. Step 5: If necessary, calculate how much is left in excess. For another example, let's start with an unbalanced equation: By inspection, you can see this equation is not balanced because mass is not conserved. If melanoma is found, youll be able to get the treatment you need. JAK inhibitors are helping patients with alopecia areata, eczema/atopic dermatitis, psoriasis, and vitiligo. Step 6: Find the amount of remaining excess reactant by subtracting the mass of the excess reagent consumed from the total mass of excess reagent given. They look like raised warts. Some people consider a mole more of a blemish than a beauty mark. Limit the amount of time your skin is exposed to sunlight. They may be surgically removed if: If the melanoma is detected in the very early stages, when the mole is thin and has not grown downwards from the surface of the skin and spread to other parts of the body, it is removed using a simple surgical technique. Given the following balanced chemical equation: \[\ce{C5H12 + 8O2 5CO2 + 6H2O} \nonumber \], How many moles of \(\ce{H2O}\) can be formed if 0.0652 mol of \(\ce{C_{5}H_{12}}\) were to react? Mole Ratio. Thus is the limiting reagent as it limits the formation of product and is the excess regaent. The ratio is 2 ozone to 3 oxygen, or 2:3. Thats why its so important to know what your moles look like. Calculate the mass of limiting reactant needed to react with the unused excess reactant. We can use these ratios to determine what amount of a substance, in moles, will react with or produce a given number of moles of a different substance. Therefore, by either method, C2H3Br3is the limiting reagent. the stoichiometry of x to y = 1:2 1 mole of x reacts with 2 moles of y if x is the limiting reactant, there are 3 moles of x, then 6 moles of y should react, however there are only 4 moles of y. Helmenstine, Anne Marie, Ph.D. (2023, April 5). Step 6: Find the amount of remaining excess reactant by subtracting the mass of the excess reactant consumed from the total mass of excess reactant given. The limiting reactant (or limiting reagent) is the reactant that determines the amount of product that can be formed in a chemical reaction. It doesn't matter which product is used for the calculation, as long as the same product is used in for the comparison. For the reactant in excess, how many moles are left over at the end of the reaction? Could monthly vitamin D supplements help prevent heart attacks? Mole Ratio: Definition and Examples. 12.7: Limiting Reactant - Chemistry LibreTexts Kaplan, E. N., & Kaplan, E. N. (1974). While people with more than 50 moles may be at higher risk of developing melanoma, people who have fewer moles may be at greater risk of developing more aggressive melanoma. Types of Moles. 0.8224 mols Cr 2 O 3 x 3 mols Si / 2 mols Cr 2 O 3 = 1.233 mols Si used. Regularly check your moles for any changes. We also acknowledge previous National Science Foundation support under grant numbers 1246120, 1525057, and 1413739. 8.6: Limiting Reactants and Excess Reactants is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by LibreTexts. If lab results come back with a suspected melanoma, further tests may be ordered to determine whether the cancer has spread. 5. The balanced chemical equation is already given. To figure out the amount of product produced, it must be determined which reactant will limit the chemical reaction (the limiting reagent) and which reactant is in excess (the excess reagent). Iron corrodes in the equation 3Fe + 4 H2 O --> F3 O4 + 4 H2 . A 2.00 g sample of ammonia reacts with 4.00 g of oxygen according to the equation. Rickard, James N.; Spencer, George M.; Bodner, Lyman H. (2010). Youll usually also still have the mole. The balanced equation shows the hydrogen and chlorine react in a 1:1 stoichiometric ratio. Identify the "given" information and what the problem is asking you to "find.". \[\ce{SiO_2+ 2 H_2F_2 \rightarrow SiF_4+ 2 H_2O} \nonumber \], \[\mathrm{28.7\:g \times \dfrac{1\: mole}{60.08\:g} = 0.478\: moles\: of\: SiO_2} \nonumber \], \[\mathrm{22.6\:g \times \dfrac{1\: mole}{39.8\:g} = 0.568\: moles\: of\: H_2F_2} \nonumber \]. #0.1250 cancel("mol O"_2) ("4 mol NH"_3)/(5 cancel("mol O"_2)) = "0.1000 mol NH"_3#, #0.1000 cancel("mol NH"_3) ("17.03 g NH"_3)/(1 cancel("mol NH"_3)) = "1.703 g NH"_3#. In this example, imagine that the tires and headlights are reactants while the car is the product formed from the reaction of 4 tires and 2 headlights. Can diet and exercise reverse prediabetes? Heres what you need to know. Melanoma, the most-serious skin cancer, can begin in a mole. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. A crucial skill in evaluating the conditions of a chemical process is to determine which reactant is the limiting reactant and which is/are the excess reactant(s). #"Moles of NH"_3 = 0.30 cancel("g NH"_3) ("1 mol NH"_3)/(17.03 cancel("g NH"_3)) = "0.0176 mol NH"_3#, #"Moles of O"_2 = 0.0176 cancel("mol NH"_3) (5 cancel("mol O"_2))/(4 cancel("mol NH"_3)) = "0.0220 mol O"_2#, #"Mass of O"_2 = 0.0220 cancel("mol O"_2) ("32.00 g O"_2)/(1 cancel("mol O"_2)) = "0.70 g O"_2#. PhET Simulation: Limiting and Excess Reactants. When a mole begins changing, it could be a sign of cancer. Find out why dark spots appear and what can fade them. . In this video, we'll determine the limiting reactant for a given reaction and use this information to calculate the theoretical yield of product. Step 3: Calculate the mole ratio from the given information. Recent developments on moles from MNT news. 6.6 mol Consider the reaction The reactants must thus occur in that ratio; otherwise, one will limit the reaction. Given the chemical equation and the masses of reactants, determine the mass of excess reactant and the mass of the limiting reactant required to use up the excess. 8.3: Mole-to-Mole Conversions is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by LibreTexts. 1.25 mol - 0.8328 mol = 0.4172 moles of oxygen left over, Calculate the mass of magnesium oxide possible if 2.40 g \(\ce{Mg}\) reacts with 10.0 g of \(\ce{O_2}\), \[\ce{ Mg +O_2 \rightarrow MgO} \nonumber \], \[\ce{2 Mg + O_2 \rightarrow 2 MgO} \nonumber \], Step 2 and Step 3: Converting mass to moles and stoichiometry, \[\mathrm{2.40\:g\: Mg \times \dfrac{1.00\: mol\: Mg}{24.31\:g\: Mg} \times \dfrac{2.00\: mol\: MgO}{2.00\: mol\: Mg} \times \dfrac{40.31\:g\: MgO}{1.00\: mol\: MgO} = 3.98\:g\: MgO} \nonumber \], \[\mathrm{10.0\:g\: O_2\times \dfrac{1\: mol\: O_2}{32.0\:g\: O_2} \times \dfrac{2\: mol\: MgO}{1\: mol\: O_2} \times \dfrac{40.31\:g\: MgO}{1\: mol\: MgO} = 25.2\: g\: MgO} \nonumber \], Step 4: The reactant that produces a smaller amount of product is the limiting reagent. The mole ratio between N_2 and NH_3 is 1:2, so one mole of nitrogen gas makes two moles of ammonia gas. Prentice Hall Chemistry. To produce 27.6 mol of H2O, 13.8 mol of O2 react. Moles can change in appearance and amount. 0.162 mol d. 0.162 mol With shaving (or cutting), you also risk getting a serious scar or infection. All moles are not created equally. Excess reactants. Accessibility StatementFor more information contact us atinfo@libretexts.org. Use the molar ratio from the equation to convert moles of #"O"_2# (from Step 3) to moles of #"NH"_3#, and then convert moles of #"NH"_3# to grams of #"NH"_3#. Dr. Helmenstine holds a Ph.D. in biomedical sciences and is a science writer, educator, and consultant. Balancing this equation yields: Now you can use the coefficients in front of ozone and oxygen to find the mole ratio. Find the limiting reagent by calculating and comparing the amount of product each reactant will produce. She has taught science courses at the high school, college, and graduate levels. If less than 6 moles of oxygen are available per mole of glucose, oxygen is the limiting reactant. This gives a 4.004 ratio of \(\ce{O2}\) to \(\ce{C6H12O6}\). \(\mathrm{\cancel{27.6\: mol\: H_2O}\times\dfrac{1\: mol\: O_2}{\cancel{2\: mol\: H_2O}}=13.8\: mol\: O_2}\). b. Brain's unique pain fingerprint could lead to personalized pain management. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. There are two ways to determine the limiting reagent. 0.0117 mold. How many moles of which reactant remain unconsumed? The lesson? 0.145 molc. Learn about treatments and when to see a, A mole removal scar will usually heal within 4 weeks, though it may be visible for months or years afterward. Everyone's at risk for skin cancer. OR. The patient will be asked to come back after a few weeks to see whether any of the dimensions have changed. Given time to grow, melanoma can spread, making treatment difficult. Sometimes they eventually fade away or drop off. A clinicopathological study of TRAIL expression in halo nevi. #"Moles of NH"_3 = 2.00 cancel("g NH"_3) ("1 mol NH"_3)/(17.03 cancel("g NH"_3)) = "0.1174 mol NH"_3#, #0.1174 cancel("mol NH") "4 mol NO"/(4 cancel("mol NH")) = "0.1174 mol NO"#. 4 NH (g) + 5 O (g) 4 NO (g) + 6 HO (g) This problem has been solved! The number of moles on ones right arm could be used to predict the risk of melanoma the deadliest form of skin cancer according to a new study by researchers from Kings College London in the UK. Balanced equation [Math Processing Error] 2. Consider thefood analogy, making grilled cheese sandwiches (Figure \(\PageIndex{1}\)): \[\text{1 slice of cheese} + \text{2 slices of bread} \rightarrow \text{1 sandwich} \label{4.5.A}\]. You should also see your doctor if a mole itches, has a burning sensation, is painful, bleeds or oozes, is crusty or scaly, or suddenly changes in color, elevation, size, or shape. Moles are small skin lesions consisting of cells that produce melanin. (second edition). Answered: If 8.00 moles of NH of and 10.00 moles | bartleby In general, moles are brown; however, they can come in a variety of sizes, shapes and colors: A moles surface can be raised, wrinkled, flat, or smooth. Excess reactant therefore is Si. For the reaction:2 H2(g) + O2(g) 2 H2O(g). Because there is an excess of oxygen, the glucose amount is used to calculate the amount of the products in the reaction. Complete reaction of the provided chlorine would produce: \(2\:\cancel{\mathrm{mol}\:{\mathrm{Cl}}_2}\times\dfrac{2\:\mathrm{mol}\:\mathrm{HCl}}{1\:\cancel{\mathrm{mol}\:{\mathrm{Cl}}_2}}=\boxed{4\:\mathrm{mol}\:\mathrm{HCl}\;\mathrm{produced}}\). This chemistry tutorial contains plenty of examples and stoichiometry practice problems.New Chemistry Video Playlist:https://www.youtube.com/watch?v=bka20Q9TN6M\u0026t=25s\u0026list=PL0o_zxa4K1BWziAvOKdqsMFSB_MyyLAqS\u0026index=1Access to Premium Videos:https://www.patreon.com/MathScienceTutor (See Example. Dermatologists care for people of all ages. Solved If 8.00 moles of NH of and 10.00 moles of O react - Chegg If 4 moles of hydrogen were used, then 4 moles of water would be produced. Ankylosing Spondylitis Pain: Fact or Fiction, http://ttps://www.aad.org/public/diseases/bumps-and-growths/moles, http://journals.lww.com/plasreconsurg/citation/1974/04000/the_risk_of_malignancy_in_large_congenital_nevi.7.aspx, http://onlinelibrary.wiley.com/doi/10.1111/jdv.14059/full, http://linkinghub.elsevier.com/retrieve/pii/S0738081X13000965?via=sd&cc=y, http://www.ijcem.com/files/ijcem0036933.pdf, Fluctuating cholesterol, triglyceride levels may influence dementia risk, Multiple sclerosis treatment could improve with discovery of genetic marker. { "8.01:_Climate_Science_And_Carbon_Dioxide" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass230_0.b__1]()", "8.02:_An_Automobile_Factory" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass230_0.b__1]()", "8.03:_Stoichiometry_and_the_Molar_Interpretation" : "property get [Map 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{\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), Example \(\PageIndex{1}\): Limiting Reactants andMole-to-Mole Calculations, \({\color[rgb]{0.8, 0.0, 0.0}\boxed{\mathrm{mol}\;{\mathrm C}_2{\mathrm H}_3{\mathrm{Br}}_3}}\xrightarrow[{4\;\mathrm{mol}\;{\mathrm C}_2{\mathrm H}_3{\mathrm{Br}}_3}]{6\;\mathrm{mol}\;{\mathrm{Br}}_2}{\color[rgb]{0.0, 0.0, 1.0}\boxed{\;\;\;\mathrm{mol}\;{\mathrm{Br}}_2\;\;\;}}\), Example \(\PageIndex{2}\): Limiting Reactants and Mass-to-MassCalculations, \({\color[rgb]{0.5, 0.0, 0.5}\boxed{\;\mathrm g\;{\mathrm C}_2{\mathrm H}_3{\mathrm{Br}}_3\;}}\xrightarrow[{266.74\;\mathrm g\;{\mathrm C}_2{\mathrm H}_3{\mathrm{Br}}_3}]{1\;\mathrm{mol}\;{\mathrm C}_2{\mathrm H}_3{\mathrm{Br}}_3}{\color[rgb]{0.8, 0.0, 0.0}\boxed{\mathrm{mol}\;{\mathrm C}_2{\mathrm H}_3{\mathrm{Br}}_3}}\xrightarrow[{4\;\mathrm{mol}\;{\mathrm C}_2{\mathrm H}_3{\mathrm{Br}}_3}]{8\;\mathrm{mol}\;{\mathrm{CO}}_2}{\color[rgb]{0.0, 0.0, 1.0}\boxed{\;\mathrm{mol}\;{\mathrm{CO}}_2\;}}\xrightarrow[{1\;\mathrm{mol}\;{\mathrm{CO}}_2}]{44.01\;\mathrm g\;{\mathrm{CO}}_2}{\color[rgb]{0.0, 0.5, 0.0}\boxed{\;\;\;\mathrm g\;{\mathrm{CO}}_2\;\;\;}}\), \({\color[rgb]{0.5, 0.0, 0.5}\boxed{\;\;\;\;\mathrm g\;{\mathrm O}_2\;\;\;\;}}\xrightarrow[{32.00\;\mathrm g\;{\mathrm O}_2}]{1\;\mathrm{mol}\;{\mathrm O}_2}{\color[rgb]{0.8, 0.0, 0.0}\boxed{\;\;\;\mathrm{mol}\;{\mathrm O}_2\;\;\;}}\xrightarrow[{11\;\mathrm{mol}\;{\mathrm O}_2}]{8\;\mathrm{mol}\;{\mathrm{CO}}_2}{\color[rgb]{0.0, 0.0, 1.0}\boxed{\;\;\mathrm{mol}\;{\mathrm{CO}}_2\;\;}}\xrightarrow[{1\;\mathrm{mol}\;{\mathrm{CO}}_2}]{44.01\;\mathrm g\;{\mathrm{CO}}_2}{\color[rgb]{0.0, 0.5, 0.0}\boxed{\;\;\;\;\mathrm g\;{\mathrm{CO}}_2\;\;\;\;}}\), Example \(\PageIndex{3}\): Limiting Reactant and Mass of Excess Reactant, \({\color[rgb]{0.5, 0.0, 0.5}\boxed{\;\;\;\mathrm g\;\mathrm{Rb}\;\;\;}}\xrightarrow[{85.47\;\mathrm g\;\mathrm{Rb}}]{1\;\mathrm{mol}\;\mathrm{Rb}}{\color[rgb]{0.8, 0.0, 0.0}\boxed{\;\;\mathrm{mol}\;\mathrm{Rb}\;\;}}\xrightarrow[{2\;\mathrm{mol}\;\mathrm{Rb}}]{1\;\mathrm{mol}\;\mathrm{Mg}}{\color[rgb]{0.0, 0.0, 1.0}\boxed{\;\;\mathrm{mol}\;\mathrm{Mg}\;\;}}\xrightarrow[{1\;\mathrm{mol}\;\mathrm{Mg}}]{24.31\;\mathrm g\;\mathrm{Mg}}{\color[rgb]{0.0, 0.5, 0.0}\boxed{\;\;\;\mathrm g\;\mathrm{Mg}\;\;\;}}\), Identify the "given" information and what the problem is asking you to "find.".